platypus is just another mammal. To understand the
platypus, it is important to know how it is
different from other mammals. To understand the constructor, it is
similarly important
to understand how it differs from a method.
Any student of Java, especially one studying for certification, needs to
know
those differences; in this article, I will
concretely spell them out. Table 1, at the end of this article,
summarizes the
key constructor/method distinctions.
Purpose and function
Constructors have one purpose in life: to create an instance of a class. This can also be called creating an object, as in:
Platypus p1 = new Platypus();
The purpose of methods, by contrast, is much more general. A method's basic function is to execute Java code.
Signature differences
Constructors and methods differ in three aspects of the signature: modifiers, return type, and name. Like methods, constructors
can have any of the access modifiers: public, protected, private, or none (often called package or friendly). Unlike methods, constructors can take only access modifiers. Therefore, constructors cannot be
abstract
, final
, native
, static
, or synchronized
.The return types are very different too. Methods can have any valid return type, or no return type, in which case the return
type is given as
void
. Constructors have no return type, not even void
.Finally, in terms of the signature,
methods and constructors have different names. Constructors have the
same name as their
class; by convention, methods use names
other than the class name. If the Java program follows normal
conventions, methods
will start with a lowercase letter,
constructors with an uppercase letter. Also, constructor names are
usually nouns because
class names are usually nouns; method
names usually indicate actions.
The use of "this"
Constructors and methods use the keyword
this
quite differently. A method uses this
to refer to the instance of the class that is executing the method. Static methods do not use this
; they do not belong to a class instance, so this
would have nothing to reference. Static methods belong to the class as a whole, rather than to an instance. Constructorsuse
this
to refer to another constructor in the same class with a different parameter list. Study the following code:public class Platypus {
String name;
Platypus(String input) {
name = input;
}
Platypus() {
this("John/Mary Doe");
}
public static void main(String args[]) {
Platypus p1 = new Platypus("digger");
Platypus p2 = new Platypus();
}
}
In the code, there are two constructors. The first takes a
String
input to name the instance. The second, taking no parameters, calls the first constructor by the default name "John/Mary Doe"
.If a constructor uses
this
, it must be in the constructor's first line; ignoring this rule will cause the compiler to object.
The use of "super"
Methods and constructors both use
super
to refer to a superclass, but in different ways. Methods use super
to execute an overridden method in the superclass, as the following example illustrates:class Mammal {
void getBirthInfo() {
System.out.println("born alive.");
}
}
class Platypus extends Mammal {
void getBirthInfo() {
System.out.println("hatch from eggs");
System.out.print("a mammal normally is ");
super.getBirthInfo();
}
}
In the above program, the call to
super.getBirthInfo()
calls the overridden method of the Mammal
superclass.Constructors use
super
to invoke the superclass's constructor. If a constructor uses super
, it must use it in the first line; otherwise, the compiler will complain. An example follows:public class SuperClassDemo {
SuperClassDemo() {}
}
class Child extends SuperClassDemo {
Child() {
super();
}
}
In the above (and trivial!) example, the constructor
Child()
includes a call to super
, which causes the class SuperClassDemo
to be instantiated, in addition to the Child
class.
Compiler-supplied code
The new Java programmer may stumble when
the compiler automatically supplies code for constructors. This happens
if you write
a class with no constructors; the compiler
will automatically supply a no-argument constructor for you. Thus, if
you write:
public class Example {}
it is functionally equivalent to writing:
public class Example {
Example() {}
}
The compiler also automatically supplies code when you do not use
super
(using zero or more parameters) as the first line of a constructor. In this case, the computer automatically inserts super
. Thus, if you write:public class TestConstructors {
TestConstructors() {}
}
it is functionally equivalent to writing:
public class TestConstructors {
TestConstructors() {
super
;
}
}
The sharp-eyed beginner may wonder how the above program can call the parent class's constructor when
TestConstructor
is not extending any class. The answer is that Java extends the Object
class when you do not explicitly extend a class. The compiler
automatically supplies a no-argument constructor if no constructor
is explicitly declared, and automatically
supplies a no-argument
super
call when a constructor has no explicit call to super
. So the following two code snippets are functionally equivalent:public class Example {}
and
public class Example {
Example() {
super
;
}
}
Inheritance
What is wrong with the following scenario? A lawyer is reading the will of
A. Class
. Members of the Class
family are gathered around a large conference table, some sobbing gently. The lawyer reads, "I, A. Class
, being of sound mind and body, leave all my constructors to my children."The problem is that constructors cannot be inherited. Fortunately for the
Class
children, they will automatically inherit any of their parents' methods, so the Class
children will not become totally destitute.Remember, Java methods are inherited, constructors are not. Consider the following class:
public class Example {
public void sayHi {
system.out.println("Hi");
}
Example() {}
}
public class SubClass extends Example {
}
The
SubClass
class automatically inherits the sayHi
method found in the parent class. However, the constructor Example()
is not inherited by the SubClass
.
Summarizing the differences
Just as the platypus differs from the typical mammal, so too do constructors differ from methods; specifically in their purpose,
signature, and use of
this
and super
.Additionally, constructors differ with respect to inheritance and
compiler-supplied code. Keeping all these details straight
can be a chore; the following table
provides a convenient summary of the salient points. You can find more
information regarding
constructors and methods in the Resources section below.
About the author
Robert Nielsen is a Sun Certified Java 2
Programmer. He holds a master's degree in education, specializing
in computer-assisted instruction, and has taught in the computer
field for several years. He has also published computer-related
articles in a variety of magazines.Table 1. Differences Between Constructors and Methods
Topic | Constructors | Methods |
---|---|---|
Purpose | Create an instance of a class | Group Java statements |
Modifiers | Cannot be abstract , final , native , static , or synchronized | Can be abstract , final , native , static , or synchronized |
Return type | No return type, not even void | void or a valid return type |
Name | Same name as the class (first letter is capitalized by convention) -- usually a noun | Any name except the class. Method names begin with a lowercase letter by convention -- usually the name of an action |
this | Refers to another constructor in the same class. If used, it must be the first line of the constructor | Refers to an instance of the owning class. Cannot be used by static methods |
super | Calls the constructor of the parent class. If used, must be the first line of the constructor | Calls an overridden method in the parent class |
Inheritance | Constructors are not inherited | Methods are inherited |
Compiler automatically supplies a default constructor | If the class has no constructor, a no-argument constructor is automatically supplied | Does not apply |
Compiler automatically supplies a default call to the superclass constructor | If the constructor makes no zero-or-more argument calls to super , a no-argument call to super is made | Does not apply |
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